Modulasi pita sisi vestigial: Béda antarrépisi
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Baris ka-10:
Dumasar kana gambar kasebut:
X<sub>DSB</sub>(<math>\omega</math>) = <math>M (\omega - \omega_c) + M (\omega + \omega_c)</math> ....... (1)
sarta:
X<sub>VSB</sub>(<math>\omega</math>) = <math>[M(\omega - \omega_c) + M(\omega + \omega_c)]H(\omega)</math> .......(2)
==Demodulasi sinyal VSB==
Baris ka-23:
Katempo yen d(t) = x<sub>VSB</sub>(t)<math>cos \omega_c t</math> boga [[transformasi Fourier]]:
<math>\frac {1}{2}</math>[X<sub>VSB</sub><math>(\omega - \omega_c)</math> + X<sub>VSB</sub><math>(\omega + \omega_c)]</math> ......(3)
Ku cara ngasupkeun persamaan (2) kana persamaan (3), mangka dihasilkeun:
<math>\frac {1}{2} [[M(\omega - 2\omega_c) + M(\omega)] H (\omega - \omega_c) + [M(\omega) + M(\omega + 2\omega_c)]H(\omega + \omega_c)]</math> .......(4)▼
Ku cara nindes spektrum dina <math>-2\omega_c</math> jeung <math>+2\omega_c</math> make [[LPF]], urang baris meunangkeun y(t) ti demodulator VSB sinkron sarta [[transformasi Fourier]]na:
<math> y(t) \stackrel{\mathcal{F}} \frac {1}{2} [[M(\omega) [H (\omega + \omega_c) + H(\omega - \omega_c)]]</math> .......(5)
▲<math>\frac {1}{2} [[M(\omega - 2\omega_c) + M(\omega)] H (\omega - \omega_c) + [M(\omega) + M(\omega + 2\omega_c)]H(\omega + \omega_c)]</math>
==Tempo ogé==
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